SetDiff1d

public final class SetDiff1d

Computes the difference between two lists of numbers or strings.

Given a list `x` and a list `y`, this operation returns a list `out` that represents all values that are in `x` but not in `y`. The returned list `out` is sorted in the same order that the numbers appear in `x` (duplicates are preserved). This operation also returns a list `idx` that represents the position of each `out` element in `x`. In other words:

`out[i] = x[idx[i]] for i in [0, 1, ..., len(out) - 1]`

For example, given this input: 

x = [1, 2, 3, 4, 5, 6]
 y = [1, 3, 5]
This operation would return: 
out ==> [2, 4, 6]
 idx ==> [1, 3, 5]

Constants

String OP_NAME The name of this op, as known by TensorFlow core engine

Public Methods

static <T extends TType, U extends TNumber> SetDiff1d<T, U>
create(Scope scope, Operand<T> x, Operand<T> y, Class<U> outIdx)
Factory method to create a class wrapping a new SetDiff1d operation.
static <T extends TType> SetDiff1d<T, TInt32>
create(Scope scope, Operand<T> x, Operand<T> y)
Factory method to create a class wrapping a new SetDiff1d operation using default output types.
Output<U>
idx()
1-D.
Output<T>
out()
1-D.

Inherited Methods

Constants

public static final String OP_NAME

The name of this op, as known by TensorFlow core engine

Constant Value: "ListDiff"

Public Methods

public static SetDiff1d<T, U> create (Scope scope, Operand<T> x, Operand<T> y, Class<U> outIdx)

Factory method to create a class wrapping a new SetDiff1d operation.

Parameters
scope current scope
x 1-D. Values to keep.
y 1-D. Values to remove.
Returns
  • a new instance of SetDiff1d

public static SetDiff1d<T, TInt32> create (Scope scope, Operand<T> x, Operand<T> y)

Factory method to create a class wrapping a new SetDiff1d operation using default output types.

Parameters
scope current scope
x 1-D. Values to keep.
y 1-D. Values to remove.
Returns
  • a new instance of SetDiff1d

public Output<U> idx ()

1-D. Positions of `x` values preserved in `out`.

public Output<T> out ()

1-D. Values present in `x` but not in `y`.