tensorflow:: ops:: UnsortedSegmentMin

Computes the minimum along segments of a tensor.

Summary

Read the section on segmentation for an explanation of segments.

This operator is similar to the unsorted segment sum operator found (here) . Instead of computing the sum over segments, it computes the minimum such that:

\(output_i = {j...} data_[j...]\) where min is over tuples j... such that segment_ids[j...] == i .

If the minimum is empty for a given segment ID i , it outputs the largest possible value for the specific numeric type, output[i] = numeric_limits ::max() .

For example:

c = tf.constant([[1,2,3,4], [5,6,7,8], [4,3,2,1]])
tf.unsorted_segment_min(c, tf.constant([0, 1, 0]), num_segments=2)
# ==> [[ 1,  2, 2, 1],
#       [5,  6, 7, 8]]

If the given segment ID i is negative, then the corresponding value is dropped, and will not be included in the result.

Args:

• scope: A Scope object
• segment_ids: A tensor whose shape is a prefix of data.shape .

Returns:

• Output : Has same shape as data, except for the first segment_ids.rank dimensions, which are replaced with a single dimension which has size num_segments .

Public attributes

Operation operation

::tensorflow::Output output

Public functions

 UnsortedSegmentMin(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input data,
  ::tensorflow::Input segment_ids,
  ::tensorflow::Input num_segments
)

::tensorflow::Node * node() const 

 operator::tensorflow::Input() const 

 operator::tensorflow::Output() const