tf.math.minimum

TensorFlow 1 version

Returns the min of x and y (i.e. x < y ? x : y) element-wise.

tf.math.minimum(
    x, y, name=None
)

Both inputs are number-type tensors (except complex). minimum expects that both tensors have the same dtype.

Examples:

x = tf.constant([0., 0., 0., 0.])
y = tf.constant([-5., -2., 0., 3.])
tf.math.minimum(x, y)
<tf.Tensor: shape=(4,), dtype=float32, numpy=array([-5., -2., 0., 0.], dtype=float32)>

Note that minimum supports broadcast semantics.

x = tf.constant([-5., 0., 0., 0.])
y = tf.constant([-3.])
tf.math.minimum(x, y)
<tf.Tensor: shape=(4,), dtype=float32, numpy=array([-5., -3., -3., -3.], dtype=float32)>

If inputs are not tensors, they will be converted to tensors. See tf.convert_to_tensor.

x = tf.constant([-3.], dtype=tf.float32)
tf.math.minimum([-5], x)
<tf.Tensor: shape=(1,), dtype=float32, numpy=array([-5.], dtype=float32)>

x A Tensor. Must be one of the following types: bfloat16, half, float32, float64, uint8, int16, int32, int64.
y A Tensor. Must have the same type as x.
name A name for the operation (optional).

A Tensor. Has the same type as x.