Scatter updates into an existing tensor according to indices.
tfp.experimental.distributions.marginal_fns.ps.tensor_scatter_nd_update(
tensor, indices, updates, name=None
)
This operation creates a new tensor by applying sparse updates to the
input tensor. This is similar to an index assignment.
# Not implemented: tensors cannot be updated inplace.
tensor[indices] = updates
If an out of bound index is found on CPU, an error is returned.
- If an out of bound index is found, the index is ignored.
- The order in which updates are applied is nondeterministic, so the output will be nondeterministic if
indicescontains duplicates.
This operation is very similar to tf.scatter_nd, except that the updates are
scattered onto an existing tensor (as opposed to a zero-tensor). If the memory
for the existing tensor cannot be re-used, a copy is made and updated.
In general:
indicesis an integer tensor - the indices to update intensor.indiceshas at least two axes, the last axis is the depth of the index vectors.- For each index vector in
indicesthere is a corresponding entry inupdates. - If the length of the index vectors matches the rank of the
tensor, then the index vectors each point to scalars intensorand each update is a scalar. - If the length of the index vectors is less than the rank of
tensor, then the index vectors each point to the slices oftensorand shape of the updates must match that slice.
Overall this leads to the following shape constraints:
assert tf.rank(indices) >= 2
index_depth = indices.shape[-1]
batch_shape = indices.shape[:-1]
assert index_depth <= tf.rank(tensor)
outer_shape = tensor.shape[:index_depth]
inner_shape = tensor.shape[index_depth:]
assert updates.shape == batch_shape + inner_shape
Typical usage is often much simpler than this general form, and it can be better understood starting with simple examples:
Scalar updates
The simplest usage inserts scalar elements into a tensor by index.
In this case, the index_depth must equal the rank of the
input tensor, slice each column of indices is an index into an axis of the
input tensor.
In this simplest case the shape constraints are:
num_updates, index_depth = indices.shape.as_list()
assert updates.shape == [num_updates]
assert index_depth == tf.rank(tensor)`
For example, to insert 4 scattered elements in a rank-1 tensor with 8 elements.
This scatter operation would look like this:
tensor = [0, 0, 0, 0, 0, 0, 0, 0] # tf.rank(tensor) == 1indices = [[1], [3], [4], [7]] # num_updates == 4, index_depth == 1updates = [9, 10, 11, 12] # num_updates == 4print(tf.tensor_scatter_nd_update(tensor, indices, updates))tf.Tensor([ 0 9 0 10 11 0 0 12], shape=(8,), dtype=int32)
The length (first axis) of updates must equal the length of the indices:
num_updates. This is the number of updates being inserted. Each scalar
update is inserted into tensor at the indexed location.
For a higher rank input tensor scalar updates can be inserted by using an
index_depth that matches tf.rank(tensor):
tensor = [[1, 1], [1, 1], [1, 1]] # tf.rank(tensor) == 2indices = [[0, 1], [2, 0]] # num_updates == 2, index_depth == 2updates = [5, 10] # num_updates == 2print(tf.tensor_scatter_nd_update(tensor, indices, updates))tf.Tensor([[ 1 5][ 1 1][10 1]], shape=(3, 2), dtype=int32)
Slice updates
When the input tensor has more than one axis scatter can be used to update
entire slices.
In this case it's helpful to think of the input tensor as being a two level
array-of-arrays. The shape of this two level array is split into the
outer_shape and the inner_shape.
indices indexes into the outer level of the input tensor (outer_shape).
and replaces the sub-array at that location with the corresponding item from
the updates list. The shape of each update is inner_shape.
When updating a list of slices the shape constraints are:
num_updates, index_depth = indices.shape.as_list()
outer_shape = tensor.shape[:index_depth]
inner_shape = tensor.shape[index_depth:]
assert updates.shape == [num_updates, inner_shape]
For example, to update rows of a (6, 3) tensor:
tensor = tf.zeros([6, 3], dtype=tf.int32)Use an index depth of one.
indices = tf.constant([[2], [4]]) # num_updates == 2, index_depth == 1num_updates, index_depth = indices.shape.as_list()
The outer_shape is 6, the inner shape is 3:
outer_shape = tensor.shape[:index_depth]inner_shape = tensor.shape[index_depth:]
2 rows are being indexed so 2 updates must be supplied.
Each update must be shaped to match the inner_shape.
# num_updates == 2, inner_shape==3updates = tf.constant([[1, 2, 3],[4, 5, 6]])
Altogether this gives:
tf.tensor_scatter_nd_update(tensor, indices, updates).numpy()array([[0, 0, 0],[0, 0, 0],[1, 2, 3],[0, 0, 0],[4, 5, 6],[0, 0, 0]], dtype=int32)
More slice update examples
A tensor representing a batch of uniformly sized video clips naturally has 5
axes: [batch_size, time, width, height, channels].
For example:
batch_size, time, width, height, channels = 13,11,7,5,3video_batch = tf.zeros([batch_size, time, width, height, channels])
To replace a selection of video clips:
- Use an
index_depthof 1 (indexing theouter_shape:[batch_size]) - Provide updates each with a shape matching the
inner_shape:[time, width, height, channels].
To replace the first two clips with ones:
indices = [[0],[1]]new_clips = tf.ones([2, time, width, height, channels])tf.tensor_scatter_nd_update(video_batch, indices, new_clips)
To replace a selection of frames in the videos:
indicesmust have anindex_depthof 2 for theouter_shape:[batch_size, time].updatesmust be shaped like a list of images. Each update must have a shape, matching theinner_shape:[width, height, channels].
To replace the first frame of the first three video clips:
indices = [[0, 0], [1, 0], [2, 0]] # num_updates=3, index_depth=2new_images = tf.ones([# num_updates=3, inner_shape=(width, height, channels)3, width, height, channels])tf.tensor_scatter_nd_update(video_batch, indices, new_images)
Folded indices
In simple cases it's convenient to think of indices and updates as
lists, but this is not a strict requirement. Instead of a flat num_updates,
the indices and updates can be folded into a batch_shape. This
batch_shape is all axes of the indices, except for the innermost
index_depth axis.
index_depth = indices.shape[-1]
batch_shape = indices.shape[:-1]
updates must have a matching batch_shape (the axes before inner_shape).
assert updates.shape == batch_shape + inner_shape
With this generalization the full shape constraints are:
assert tf.rank(indices) >= 2
index_depth = indices.shape[-1]
batch_shape = indices.shape[:-1]
assert index_depth <= tf.rank(tensor)
outer_shape = tensor.shape[:index_depth]
inner_shape = tensor.shape[index_depth:]
assert updates.shape == batch_shape + inner_shape
For example, to draw an X on a (5,5) matrix start with these indices:
tensor = tf.zeros([5,5])indices = tf.constant([[[0,0],[1,1],[2,2],[3,3],[4,4]],[[0,4],[1,3],[2,2],[3,1],[4,0]],])indices.shape.as_list() # batch_shape == [2, 5], index_depth == 2[2, 5, 2]
Here the indices do not have a shape of [num_updates, index_depth], but a
shape of batch_shape+[index_depth].
Since the index_depth is equal to the rank of tensor:
outer_shapeis(5,5)inner_shapeis()- each update is scalarupdates.shapeisbatch_shape + inner_shape == (5,2) + ()
updates = [[1,1,1,1,1],[1,1,1,1,1],]
Putting this together gives:
tf.tensor_scatter_nd_update(tensor, indices, updates).numpy()array([[1., 0., 0., 0., 1.],[0., 1., 0., 1., 0.],[0., 0., 1., 0., 0.],[0., 1., 0., 1., 0.],[1., 0., 0., 0., 1.]], dtype=float32)
Args | |
|---|---|
tensor
|
Tensor to copy/update. |
indices
|
Indices to update. |
updates
|
Updates to apply at the indices. |
name
|
Optional name for the operation. |
Returns | |
|---|---|
| A new tensor with the given shape and updates applied according to the indices. |