tensorflow:: ops:: SegmentSum
  #include <math_ops.h>
  Computes the sum along segments of a tensor.
Summary
Read the section on segmentation for an explanation of segments.
Computes a tensor such that \(output_i =  data_j\) where sum is over j such that segment_ids[j] == i.
If the sum is empty for a given segment ID i, output[i] = 0.
    
    
For example:
c = tf.constant([[1,2,3,4], [4, 3, 2, 1], [5,6,7,8]]) tf.segment_sum(c, tf.constant([0, 0, 1])) # ==> [[5, 5, 5, 5], # [5, 6, 7, 8]]
Arguments:
- scope: A Scope object
 - segment_ids: A 1-D tensor whose size is equal to the size of 
data's first dimension. Values should be sorted and can be repeated. 
Returns:
Output: Has same shape as data, except for dimension 0 which has sizek, the number of segments.
        Constructors and Destructors | 
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        SegmentSum(const ::tensorflow::Scope & scope, ::tensorflow::Input data, ::tensorflow::Input segment_ids)
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        Public attributes | 
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        operation
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        output
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        Public functions | 
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        node() const 
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        ::tensorflow::Node *
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        operator::tensorflow::Input() const 
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        operator::tensorflow::Output() const 
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Public attributes
operation
Operation operation
output
::tensorflow::Output output
Public functions
SegmentSum
SegmentSum( const ::tensorflow::Scope & scope, ::tensorflow::Input data, ::tensorflow::Input segment_ids )
node
::tensorflow::Node * node() const
operator::tensorflow::Input
operator::tensorflow::Input() const
operator::tensorflow::Output
operator::tensorflow::Output() const