tf.math.l2_normalize
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Normalizes along dimension axis
using an L2 norm.
tf.math.l2_normalize(
x, axis=None, epsilon=1e-12, name=None
)
For a 1-D tensor with axis = 0
, computes
output = x / sqrt(max(sum(x**2), epsilon))
For x
with more dimensions, independently normalizes each 1-D slice along
dimension axis
.
Args |
x
|
A Tensor .
|
axis
|
Dimension along which to normalize. A scalar or a vector of
integers.
|
epsilon
|
A lower bound value for the norm. Will use sqrt(epsilon) as the
divisor if norm < sqrt(epsilon) .
|
name
|
A name for this operation (optional).
|
Returns |
A Tensor with the same shape as x .
|
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Last updated 2020-10-01 UTC.
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